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Home/ Questions/Q 3694336
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T04:29:04+00:00 2026-05-19T04:29:04+00:00

This compiles fine, although I wouldn’t want to try running it just yet. However

  • 0

This compiles fine, although I wouldn’t want to try running it just yet. However …

//class base;
//class derived;
//class derived : public base;

class base {};
class derived : public base {};

class other
{
    public:
        void func() {base1 = derived1;}
        base* base1;
        derived* derived1;
};

void main()
{
}

… moving the class other to above the definition of base and derived for which there is a similar thing I must do in a program of myne causes compile errors.

The obvious solution is to forward declare base and derived shown commented out at the top of the code, however this causes a can’t convert between base* and derived* error. Attempting to forward declare including the inheritance information dosn’t work either.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T04:29:05+00:00Added an answer on May 19, 2026 at 4:29 am

    This should work. You need to move other up

    BUT declare func below. That way func is able to “see” that derived is of type base.

    e.g.,

    class base;
    class derived;
    //class derived : public base;
    
    class other
    {
        public:
            void func();
            base* base1;
            derived* derived1;
    };
    
    class base {};
    class derived : public base {};
    
    void other::func() { base1 = derived1; }
    
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