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Home/ Questions/Q 221603
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:02:56+00:00 2026-05-11T19:02:56+00:00

This doesn’t work: >>> pa = Person.objects.all() >>> pa[2].nickname u’arst’ >>> pa[2].nickname = ‘something

  • 0

This doesn’t work:

>>> pa = Person.objects.all()
>>> pa[2].nickname
u'arst'
>>> pa[2].nickname = 'something else'
>>> pa[2].save()
>>> pa[2].nickname  
u'arst'

But it works if you take

   p = Person.objects.get(pk=2)

and change the nick.

Why so.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T19:02:56+00:00Added an answer on May 11, 2026 at 7:02 pm
    >>> type(Person.objects.all())
    <class 'django.db.models.query.QuerySet'>
    
    >>> pa = Person.objects.all() # Not evaluated yet - lazy
    >>> type(pa)
    <class 'django.db.models.query.QuerySet'>
    

    DB queried to give you a Person object

    >>> pa[2]
    

    DB queried again to give you yet another Person object.

    >>> pa[2].first_name = "Blah" 
    

    Let’s call this instance PersonObject1 that resides in memory. So it’s equivalent to something like this:

    >>> PersonObject1.first_name = "Blah"
    

    Now let’s do this:

    >>> pa[2].save() 
    

    The pa[2] again queries a db an returns Another instance of person object, say PersonObject2 for example. Which will be unchanged! So it’s equvivalent to calling something like:

    PersonObject2.save()
    

    But this has nothing to do with PersonObject1.

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