This example uses a common variadic template and function. I want to print out the arguments passed to f:
#include <iostream>
template <typename T>
void print(T t)
{
std::cout << t << std::endl;
}
template <typename...T>
void f(T &&...args)
{
print(args...);
f(args...);
}
int main()
{
f(2, 1, 4, 3, 5);
}
But I am getting the following errors:
Compilation finished with errors:<br>
source.cpp: In instantiation of '`void f(T ...)` [with `T = {int, int, int, int, int}`]':<br>
source.cpp:16:20: required from here <br>
source.cpp:10:4: error: no matching function for call to '`print(int&, int&, int&, int&, int&)`'<br>
source.cpp:10:4: note: candidate is:<br>
source.cpp:4:6: note: `template<class T> void print(T)`<br>
source.cpp:4:6: note: template argument deduction/substitution failed:
source.cpp:10:4: note: candidate expects 1 argument, 5 provided
This is actually my first time using variadic functions and I do not exactly understand how to use them well.
I also do not get why this isn’t working and what I can do to help it.
There you go. You had several mistakes in your code, you can see the comments between the lines below:
Note that using rvalue refs here makes no sense. You’re not storing the parameters anywhere, so simply passing them by const reference should do it. That way you’d also avoid using
std::forwardjust to keep the (useless) perfect forwarding.Therefore, you could rewrite
fas follows: