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Home/ Questions/Q 8688499
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T23:22:58+00:00 2026-06-12T23:22:58+00:00

This flat XML represents tree structure using level field. How can I get elements

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This flat XML represents tree structure using level field. How can I get elements that are deeper in the tree to the given node but only in the same branch?

So given that company name is A and I need to get company B and C (not E which is in different branch).

<Companies>
      <Company>
        <Name>A</Name>
        <Level>0</Level>
      </Company>
      <Company>
        <Name>B</Name>
        <Level>1</Level>
      </Company>
      <Company>
        <Name>C</Name>
        <Level>1</Level>
      </Company>
      <Company>
        <Name>D</Name>
        <Level>0</Level>
      </Company>
      <Company>
        <Name>E</Name>
        <Level>1</Level>
      </Company>
    </Companies>

There can be more than level one. I want it returned too.
I am using XLST 1.0.

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  1. Editorial Team
    Editorial Team
    2026-06-12T23:22:59+00:00Added an answer on June 12, 2026 at 11:22 pm

    Assume the focus node (current()) is the basis of your calculation.

    Define…

    <xsl:variable name="set1" select="following-sibling::Company[ Level &gt; current()]" />
    <xsl:variable name="set2" select="following-sibling::Company[ Level &lt; 
          preceding-sibling::Company[1]/Level][1]/preceding-sibling::Company" />
    

    Then the child companies are at the intersection of these two sets, which is…

    $set1[. = $set2]
    
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