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Home/ Questions/Q 7058427
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:06:41+00:00 2026-05-28T04:06:41+00:00

This function is supposed to set descending order numbers on an IEnumerable<Order>, but it

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This function is supposed to set descending order numbers on an IEnumerable<Order>, but it doesn’t work. Can anyone tell me what’s wrong with it?

private void orderNumberSetter(IEnumerable<Order> orders)
{
    var i = 0;            

    Action<Order, int> setOrderNumber = (Order o, int count) =>
    {
        o.orderNumber = i--;
    };

    var orderArray = orders.ToArray();
    for (i = 0; i < orders.Count(); i++)
    {
        var order = orderArray[i];
        setOrderNumber(order, i);
    }            
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:06:42+00:00Added an answer on May 28, 2026 at 4:06 am

    You are re-using i as loop variable and i gets modified in your setOrderNumber lambda – don’t modify i – it’s unclear what you meant to do, maybe the following:

    Action<Order, int> setOrderNumber = (Order o, int count) =>
    {
        o.orderNumber = count;
    };
    

    If the above is the case you could have achieved that much, much easier though, your code seems unnecessarily complex, i.e:

    for (i = 0; i < orderArray.Length; i++)
    {
        orderArray[i].orderNumber = i;
    } 
    

    or even simpler without having to create an array at all:

    int orderNum = 0;
    foreach(var order in orders)
    {
       order.orderNumber = orderNum++;
    }
    

    Edit:

    To set descending order numbers, you can determine the number of orders first then go backwards from there:

    int orderNum = orders.Count();
    foreach(var order in orders)
    {
       order.orderNumber = orderNum--;
    }
    

    Above would produce one based order numbers in descending order. Another approach, more intuitive and probably easier to maintain is to just walk the enumeration in reverse order:

    int orderNum = 0;
    foreach(var order in orders.Reverse())
    {
       order.orderNumber = orderNum++;
    }
    
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