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Home/ Questions/Q 8176289
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T23:06:32+00:00 2026-06-06T23:06:32+00:00

This is a basic question I’m sure…. I have a normal form, but one

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This is a basic question I’m sure….

I have a normal form, but one of the fields is a Country dropdown menu that I am populating with an external xml script:

<?php 
//Build countries dropdown from GeoNames database
$xmlcountries = 'http://ws.geonames.org/countryInfo';
echo '<select name="custom_country" id="custom_country">';
$countries = simplexml_load_file($xmlcountries);
echo '<option value="">Your country</option>';
foreach ($countries->country as $country) {
    echo '<option value="'.$country->geonameId.'|'.$country->countryName.'">'.$country->countryName.'</option>';
}
echo '</select>';

?>

My form is this:

<form action="update.php" method="post">
    Country:<br />
    <input type="text" name="Country" size="100" /><br />
    State:<br />
    <input type="text" name="State" size="100" /><br />
    City:<br />
    <input type="text" name="City" size="100" /><br />
    <input type="submit" value="Update Database" />
</form>

I’d like the above $country variable to take the place of the name="Country" field in the form. How do I do that?

To be clear-when I submit the form, I want the value from the country dropdown to populate the $_POST['Country'].

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  1. Editorial Team
    Editorial Team
    2026-06-06T23:06:37+00:00Added an answer on June 6, 2026 at 11:06 pm

    It seems like you just want to replace:

    <input type="text" name="Country" size="100" /><br />
    

    With this:

    <?php
    
    echo '<select name="Country" id="custom_country">';
    $countries = simplexml_load_file($xmlcountries);
    echo '<option value="">Your country</option>';
    foreach ($countries->country as $country) {
        echo '<option value="'.$country->geonameId.'|'.$country->countryName.'">'.$country->countryName.'</option>';
    }
    echo '</select><br />';
    
    ?>
    
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