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Home/ Questions/Q 6721809
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:22:23+00:00 2026-05-26T09:22:23+00:00

This is a continuation of another question I have. Consider the following code: char

  • 0

This is a continuation of another question I have.

Consider the following code:

char *hi = "hello";

char *array1[3] = 
{
    hi,
    "world",
    "there."
};

It doesn’t compile to my surprise (apparently I don’t know C syntax as well as I thought) and generates the following error:

  error: initializer element is not constant

If I change the char* into char[] it compiles fine:

char hi[] = "hello";

char *array1[3] = 
{
    hi,
    "world",
    "there."
};

Can somebody explain to me why?

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:22:23+00:00Added an answer on May 26, 2026 at 9:22 am

    In the first example (char *hi = "hello";), you are creating a non-const pointer which is initialized to point to the static const string “hello”. This pointer could, in theory, point at anything you like.

    In the second example (char hi[] = "hello";) you are specifically defining an array, not a pointer, so the address it references is non-modifiable. Note that an array can be thought of as a non-modifiable pointer to a specific block of memory.

    Your first example actually compiles without issue in C++ (my compiler, at least).

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