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Home/ Questions/Q 6871049
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:45:29+00:00 2026-05-27T03:45:29+00:00

This is a follow on from a post here > How to "fadeOut" &

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This is a follow on from a post here > How to "fadeOut" & "remove" a div in jQuery? – but we’re two years on and rather than dig that up it makes sense to make a new post.

I’ve played around with it and this works (inline JQuery)

<a onclick='$("#alert_top").fadeOut(300, function(){ $(this).remove(); });' class="alert_topClose">Link</a>

removing the div “alert_top”. But the inline link is untidy.

Attempting to achieve the same result, this doesn’t work (JQuery + link)

$(".alert_topClose").click(function(){
    $("#alert_top").fadeOut(300, function(){
        $(this).remove();
    });
});

with the link

<a class="alert_topClose">Link</a>

Any help as to why would be greatly appreciated. I can’t see what the problem is.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:45:30+00:00Added an answer on May 27, 2026 at 3:45 am

    Make sure you are executing the above code in $(document).ready() or $(). If the element is not available when jQuery tries to fetch it, it cannot attach the event handler. Try this

    $(function(){
      $(".alert_topClose").click(function(){
        $("#alert_top").fadeOut(300, function(){
          $(this).remove();
        });
      });
    });
    
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