Question

(This is a follow up question to Why is this exception is not printed? Why is it showing an error?)

Here in the below code why is the ArithmeticException not triggered?

class Exp
{
    public static void main(String args[])
    {
        float d,a=1;
        try
        {
            d=0;
            a=44/d; //no exception triggered here.. why?
            System.out.print("It's not gonna print: a="+a); 
        }
        catch(ArithmeticException e)
        {
            System.out.println("Print exception: "+e);
        }
    }
} 

Instead the output is:

It's not gonna print: a=Infinity

What happens?

Answer 1

A division by zero throws an exception for integer values, but not for floating values. This is defined in the JLS #15.17.2:

The result of a floating-point division is determined by the rules of IEEE 754 arithmetic:
[…]

• Division of a nonzero finite value by a zero results in a signed infinity. The sign is determined by the rule stated above.

If you change the type of a and d to int, you will get an exception.