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Home/ Questions/Q 4248328
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T04:14:22+00:00 2026-05-21T04:14:22+00:00

This is a followup on my previous question , I am using the 2to3

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This is a followup on my previous question, I am using the 2to3 tool as suggested by Senthil Kumaran

It seems to work well but it doesn’t pick up this part:

raise LexError,("%s:%d: Rule '%s' returned an unknown token type '%s'" % (
    func.func_code.co_filename, func.func_code.co_firstlineno,
    func.__name__, newtok.type),lexdata[lexpos:])

What should this look like in 3.2 ?

EDIT: the changes from the answer below are good, 2to3 now seems to work ok. Howevery in the setup.py build I now get the error below, see my new question.

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  1. Editorial Team
    Editorial Team
    2026-05-21T04:14:23+00:00Added an answer on May 21, 2026 at 4:14 am

    Remove the comma after LexError. That works in both Python 2 and Python 3.

    In Python 2 there was a rarely used syntax to raise exceptions like this:

    raise ExceptionClass, "The message string"
    

    This is the one used here, but for some reason, maybe since there is a parenthesis around the message string (according to Senthils tests, it’s the line break in the parenthesis that does it), 2to3 misses the change into the much better:

    raise ExceptionClass("The message string")
    

    So it should look like this (in Python 2)

    message = "%s:%d: Rule '%s' returned an unknown token type '%s'" % (
               func.func_code.co_filename, func.func_code.co_firstlineno,
               func.__name__, newtok.type),lexdata[lexpos:])
    raise LexError(message)
    

    Because formatting that message on the same line as the raise is fugly. 🙂
    Then in addition func_code has been renamed, so in Python 3 there are more changes. But with the above change 2to3 should work correctly.

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