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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:25:52+00:00 2026-05-14T06:25:52+00:00

This is a little tricky so bear with me: I have a PHP script

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This is a little tricky so bear with me:

  • I have a PHP script a.php that is launched from the command line and data is provided to it via STDIN
  • I have another PHP script b.php
  • I want to have a.php launch b.php and capture its output.
  • Also, a.php has to forward the STDIN to b.php

Is there an easy way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:25:53+00:00Added an answer on May 14, 2026 at 6:25 am

    For just capturing the stdout of another program (php or not), you can use backticks:
    http://php.net/manual/en/language.operators.execution.php.
    For example:

    $boutput = `php b.php`;
    

    To capture stdin, do this:

    $ainput = file_get_contents('php://stdin');
    

    Finally, to pipe the contents of a string to an external program, use proc_open, as suggested by jeremy’s answer.
    Specifically, here’s what your a.php should contain:

    $ainput = file_get_contents('php://stdin');
    $descriptorspec = array(
            0 => array("pipe", "r"),
            1 => array("pipe", "w"),
            2 => array("pipe", "w")
    );
    $process = proc_open('php b.php', $descriptorspec, $pipes);
    fwrite($pipes[0], $ainput);
    fclose($pipes[0]);
    echo stream_get_contents($pipes[1]); # echo output of "b.php < stdin-from-a.php"
    fclose($pipes[1]);
    proc_close($process);
    
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