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Home/ Questions/Q 7863537
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T23:30:50+00:00 2026-06-02T23:30:50+00:00

This is a newbie question. To create a formatted C string, I use printf

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This is a newbie question. To create a formatted C string, I use printf, like:

int n = 10;
printf("My number is %i", 10);

But, how about:

int n = 10
char *msg = "My number is %i", 10;
printf(msg);

How can I store the resulting formatted string in a variable? I want “My number is 10”.

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  1. Editorial Team
    Editorial Team
    2026-06-02T23:30:52+00:00Added an answer on June 2, 2026 at 11:30 pm

    You want to use snprintf():

    int n = 10;
    char bla[32];   // Use an array which is large enough 
    snprintf(bla, sizeof(bla), "My number is %i", n);
    

    Do not use sprintf(); it is similar to snprintf but does not perform any buffer size checking so it is considered a security hole – of course you might always allocate enough memory but you might forget to it at some point and thus open a huge security hole.

    If you want the function to allocate memory for you, you can use asprintf() instead:

    int n = 10;
    char *bla;
    asprintf(&bla, "My number is %i", n);
    // do something with bla
    free(bla); // release the memory allocated by asprintf.
    
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