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Home/ Questions/Q 6624827
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:42:01+00:00 2026-05-25T21:42:01+00:00

This is a program to store details of an employee in a structure. Although

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This is a program to store details of an employee in a structure. Although the program runs it shows many errors, it does not give me a chance to enter address. Why is the program not running properly . Where am I going wrong ?

#include <stdio.h>
#include <conio.h>

struct details
{
 char name[30];
 int age;
 char address[500];
 float salary;
};

int main()
{
 struct details detail;
 clrscr();
 printf("\nEnter name:\n");
 gets(detail.name);
 printf("\nEnter age:\n");
 scanf("%d",&detail.age);
 printf("\nEnter Address:\n");
 gets(detail.address);
 printf("\nEnter Salary:\n");
 scanf("%f",&detail.salary);


 printf("\n\n\n");
 printf("Name of the Employee : %s \n",detail.name);
 printf("Age of the Employee : %d \n",detail.age);
 printf("Address of the Employee : %s \n",detail.address);
 printf("Salary of the Employee : %f \n",detail.salary);

 getch();
}

This is the output I get:

enter image description here

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:42:02+00:00Added an answer on May 25, 2026 at 9:42 pm

    Statement scanf("%d",&detail.age); will read 222 but not the newline you’ve entered. This newline will remain in input buffer and pass it to next input gets().

    You can use getchar() method to remove some chars from the input buffer to avoid such problems.

    char ch;
    ....
    
    printf("\nEnter age:\n");
    scanf("%d",&detail.age);
    
    while((ch = getchar()) != '\n' && ch != EOF) { }
    
    printf("\nEnter Address:\n");
    gets(detail.address);
    

    Another problem is the incorrect use of format specifier with printf function.

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