Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 723125
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T06:04:16+00:00 2026-05-14T06:04:16+00:00

This is a query automatically generated by Taggable extension for Doctrine ORM. SELECT t.id

  • 0

This is a query automatically generated by Taggable extension for Doctrine ORM.

SELECT t.id AS t__id, t.name AS t__name, COUNT(DISTINCT i.id) AS i__0,
   (COUNT(DISTINCT i.id)) AS i__1
FROM taggable_tag t
LEFT JOIN cms__model__image_taggable_tag c ON (t.id = c.tag_id)
LEFT JOIN image i ON i.id = c.id
WHERE t.id IN
    (SELECT doctrine_subquery_alias.id
     FROM
       (SELECT DISTINCT t2.id, (COUNT(DISTINCT i2.id)) AS i2__1
        FROM taggable_tag t2
        LEFT JOIN cms__model__image_taggable_tag c2 ON (t2.id = c2.tag_id)
        LEFT JOIN image i2 ON i2.id = c2.id
        GROUP BY t2.id HAVING i2__1 > 0
        ORDER BY i2__1 DESC LIMIT 10) AS doctrine_subquery_alias)
GROUP BY t.id HAVING i__1 > 0
ORDER BY i__1 DESC

It works when using MySql, but won’t work with PostgreSql.

I get: column i2__1 not found or column i__2 not found.

Are aliases disallowed when using COUNT(DISTINCT)?
How this query should look like to work on PostgreSql?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T06:04:17+00:00Added an answer on May 14, 2026 at 6:04 am

    You could try to replace i2__1 by COUNT(DISTINCT i2.id) in the HAVING-clause of the sub-select, or remove the parenthesis around COUNT(DISTINCT i2.id).

    You might also have to add t__name to the GROUP BY-clause of the main select.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 379k
  • Answers 379k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer PHP/Java Bridge: <?php checkjavaExtension(); function report_parse_post_parameters() { // Automatically extract… May 14, 2026 at 9:39 pm
  • Editorial Team
    Editorial Team added an answer The Where method returns an IEnumerable<T>. Try adding .ToList() to… May 14, 2026 at 9:39 pm
  • Editorial Team
    Editorial Team added an answer If you are reading into a numeric variable, it can't… May 14, 2026 at 9:39 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.