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Home/ Questions/Q 8185627
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T01:55:01+00:00 2026-06-07T01:55:01+00:00

This is a question from a complete noob. I have the following code: nb='([-

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This is a question from a complete noob. I have the following code:

nb='([- ][0-9]*.[0-9]*E[-+ ][0-9]*)'
nb='([0-9,E.+-]+)'

Is nb overwritten? Or does it do something else?

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  1. Editorial Team
    Editorial Team
    2026-06-07T01:55:04+00:00Added an answer on June 7, 2026 at 1:55 am

    nb is now bound to the second string, '([0-9,E.+-]+)'. So your first assignment no longer matters. Remember that nb is simply a name which now points to the second string after previously pointing to the first one, you are not modifying any strings.

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