Question

This is a re-work/new question after I got my previous one quite wrong by asking about the wrong element so here goes…

I’m trying to match and hide a xref within the following p element with the attribute of LC LRCaseName:

<p outputclass="LC LRCaseName"><i>Naseem Akhtar v Birmingham City Council</i> [2011] EWCA Civ 383 <xref href="#Public_PUBLICLAW_PLLR_2011PLLR002">Click here for transcript</xref></p>

so that I end up with “Naseem Akhtar v Birmingham City Council [2011] EWCA Civ 383“

We have other xrefs within other p outputclasses that we need to display otherwise I would hide it with <xsl:template match="p/xref"/> as per Dimitre Novatchev ‘s suggestion.

This particular xref will always contain “Click here for transcript” but the href will vary.

thanks.

EDIT:

I have tried the following code which doesn’t make the xref background red:

<xsl:template match="p[@outputclass='LC LRCaseName']/xref">
    <fo:block background-color="red" >
        <xsl:apply-templates/>
    </fo:block>
</xsl:template> 

but if I use this:

<xsl:template match="p[@outputclass='LC LRCaseName']">
    <fo:block background-color="red" >
        <xsl:apply-templates/>
    </fo:block>
</xsl:template> 

It does make the entire P element background red and that includes the xref portion.

EDIT 2:

I have just had a thought, this system has another xsl file that has matches for xref. I’m wondering if my changes are being over-written by this file. Let me look into this further.

EDIT 3:

Just placed this very same code

<xsl:template match="p[@outputclass='LC LRCaseName']/xref" />

into dita2fo-links.xsl rather than the current file I was working on (dita2fo-elems.xsl) and it worked straight away. Obviously the links file is processed after the elems and all my matching was being overwritten by the later template matches.

Answer 1

Your match selector for the xref element could include the attribute value as well, like the following one:

p[@outputclass = 'LC LRCaseName']/xref