Question

This is a Ruby question (1.9.1)

I have the following date and time in a string:

29 Sep 2013 12:25:00.367

I first want to convert it from string to date and time and then
add 10 seconds to it and convert it back to the same string format as
above.

I wrote this code:

format = "%d %b %Y %H:%M:%S"
date_time = "29 Sep 2013 22:11:30.195"
parsed_time = DateTime.strptime(date_time, format)
puts " new date time is #{parsed_time}"

Which outputs:

new date time is 2013-09-29T22:11:30+00:00

I did not see “195”. I tried format = "%d %b %Y %H:%M:%S.%3N" and this gives:

fileOpTest:34:in `strptime': invalid date (ArgumentError) from fileOpTest:34:in `<main>'

Answer 1

This can be done very easily using the Time class. You can add to a Time by adding seconds. Then use #strftime

t= Time.parse('29 Sep 2013 12:25:00.367')
=> 2013-09-29 12:25:00 -0400
t=t + 10
=> 2013-09-29 12:25:10 -0400
t.strftime("%d %b %Y %H:%M:%S.%3N")
=> "29 Sep 2013 12:25:10.367"