Question

This is a serious problem for me. I just started working with AJAX and PHP but I can’t even get off to a good start. Any help is greatly appreciated. As result of this code, I receive a blank page, as if the query has been performed, but there are no changes in database.

<?php
$user = "login";
$pass = "password";
$con = mysql_connect("localhost","qwerty","qwerty");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("database_sky", $con);

mysql_query("INSERT INTO players (id, username, password) VALUES ('',$user, $pass)");

mysql_close($con);
?>

I have no idea whats going on. Im using Apache 2.2, PHP 5, MySql 4.1

Answer 1

your variables are never wrapped in single quotes (they are meant to be strings).

try:

INSERT INTO players 
   (id, username, password)
    VALUES ('','$user', '$pass')

Whereas your original code is evaluated like this:

INSERT INTO players (id, username, password) VALUES ('',John, pass)

this doesn’t work because you need to (most likely) enter strings. You wrote john , not 'john'

I’d recommend doing something like $query = "INSERT INTO .......";

This way you can

a) echo $query; Take the string it outputs and plug that into your PhpMyAdmin (or whatever you use as an interface to your database.

b) you can then do mysql_query($query). This makes it easier to organize (for me, in my opinion).
🙂