Question

This is a simple implementation of a sort algorithm. My question is. The array numbers, is declared and initialized in main. Then, I pass it like an argument in the function sort (Is a copy ?). Inside the sort function, numbers, now called array (a copy, as far as I know), is changed (sorted). So, why, after calling the function, the array numbers is changed (this is what I want, buy want to know why??. array scope is in sort, not main.

int main(void)
{
    int numbers[SIZE] = { 4, 15, 16, 50, 8, 23, 42, 108 };
    for (int i = 0; i < SIZE; i++)
        printf("%d ", numbers[i]);
    printf("\n");

    sort(numbers, SIZE);

    for (int i = 0; i < SIZE; i++)
        printf("%d ", numbers[i]);
    printf("\n");
    return 0;
}
void sort(int array[], int size)
{
    int swaps = 0;

    while(swaps==0)
    {
        for(int i = 0; i < size ; i++)
        {
            for(int j = i + 1; j < size ; j++)
            {
                if( array[i] > array[j] )
                {
                    // Swapping
                    int temp = array[i]; 
                    array[i] = array[j];
                    array[j] = temp;

                    swaps ++;
                }   
            }
        }
    }    
}

Answer 1

int array[] is the same as int *array. You are passing a pointer.