Question

This is a snippet of Java code:

interface Rideable {
    String getGait();
}

public class Camel implements Rideable {
    int x = 2;
    public static void main(String[] args) {
        new Camel().go(8);
    }

    void go(int speed) {
        System.out.println((++speed * x++) + this.getGait());
    }

    String getGait() {
        return " mph, lope";
    }
}

It turns out that compilation fails (according to Oracle) though in my opinion it shall run fine producing output. So, where is the culprit for failing compilation?
Cheers

Answer 1

You can’t reduce the visibility of methods you override (interface methods are public by default), try this instead:

public String getGait() {
    return " mph, lope";
}