Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6706823
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T07:33:56+00:00 2026-05-26T07:33:56+00:00

This is a what the heck is going on here question. I don’t actually

  • 0

This is a “what the heck is going on here” question. I don’t actually need a solution.

I had to replace all single backslashes in a String with double backslashes . This is what I ended up doing…

strRootDirectory = strRootDirectory.replaceAll("\\\\", "\\\\\\\\");

…where strRootDirectory is a java.lang.String above.

Now, I understand the four backslashes for the first argument: regex expects two backslashes in order to indicate a single literal backslash, and java wants them doubled up. That’s fine.

BUT, what the heck is going on with the eight backslashes for the second argument? Isn’t the replacement string supposed to be a literal (non-regex, I mean) string? I expected to need four backslashes in the second argument, in order to represent two backslashes.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T07:33:57+00:00Added an answer on May 26, 2026 at 7:33 am

    The second argument isn’t a regex-string, but a regex-replacement-string, in which the backslash also has a special meaning (it is used to escape the special character $ used for variable interpolation and is also used to escape itself).

    From The API:

    Note that backslashes (\) and dollar signs ($) in the replacement string may cause the results to be different than if it were being treated as a literal replacement string; see Matcher.replaceAll. Use Matcher.quoteReplacement(java.lang.String) to suppress the special meaning of these characters, if desired.

    — http://download.oracle.com/javase/6/docs/api/java/lang/String.html#replaceAll(…)

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I know this may be a noob question, but it's bugging the heck out
My question is essentially the same as this one here . I'm using AnkhSVN
I am having one heck of a hard time trying to figure this out.
I feel a bit embarrassed asking this questions, but how the heck can I
This might seem like a stupid question I admit. But I'm in a small
This is a difficult and open-ended question I know, but I thought I'd throw
This is my first post here and I wanted to get some input from
All, I'm wondering if this is a MySQL bug, but since I've seen others
I am having a heck of a time with this one guys. I am
This should be simple enough. Here's my one line of code that's giving me

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.