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Asked: 2026-05-27T06:42:50+00:00

This is about regex in Ruby.. I have a string, that looks like: —\n-

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This is about regex in Ruby..

I have a string, that looks like:

“—\n- PARSEFROMHERE anyrthing you can imagine numbers special characters anything ENDPARSEFROMHERE\n PARSEFROMHERE anyrthing you can imagine numbers special characters anything ENDPARSEFROMHERE\n”

How would I match everything in between PARSEFROMHERE ENDPARSEFROMHERE with some regexp?

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1 Answer

  1. Editorial Team

    Try this: 

    regexp = /\bPARSEFROMHERE\b(.*?)\bENDPARSEFROMHERE\b/m

    Everything is stored into backreference 1. But if for some magical reason you have “unbalanced” delimiters this regex will fail, miserably.

    Edit:

    regexp = /\sPARSEFROMHERE\s(.*?)\sENDPARSEFROMHERE\b/m

    According to your examples PARSEFROMHERE is always preceded-followed by space. Same goes with ENDPARSEFROMHERE but this ends in \n so I keed the word boundary anchor there..

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