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Home/ Questions/Q 8340837
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T05:17:28+00:00 2026-06-09T05:17:28+00:00

This is an open discussion about different ways to enable function overloading for parameters

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This is an open discussion about different ways to enable function overloading for parameters of only char, signed char or unsigned char type with the help of type traits in terms of C++11 template compiling.

Though satisfactory, a compound logic of std::enable_if and std::is_same type assertion (see PS) is not smart in that all matching types, particularly char in spite of signedness, are used in enumeration. Therefore I’m hoping someone can specify some other clause or compound logic that might facilitate type assertions better (maybe std::is_integral, std::is_arithmetic or std::is_signed?).

PS:

template <typename type>
void foo(std::enable_if<std::is_same<type, char>::value||std::is_same<type, signed char>::value||std::is_same<type, unsigned char>::value, type> x)
{
}
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  1. Editorial Team
    Editorial Team
    2026-06-09T05:17:30+00:00Added an answer on June 9, 2026 at 5:17 am

    If you want a type trait like that, you will have to make one yourself:

    template <typename T>
    struct is_char
    {
        static const bool value = std::is_same<T, char>::value ||
                std::is_same<T, signed char>::value ||
                std::is_same<T, unsigned char>::value;
    };
    
    template <typename T>
    void f(T t, typename std::enable_if<is_char<T>::value>::type* = 0)
    {
    } 
    
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