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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T14:32:02+00:00 2026-06-12T14:32:02+00:00

This is back to the beginning of Java 101, but I have this code

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This is back to the beginning of Java 101, but I have this code here:

    if ((d==3)&&(City.walls[x--][y])){
        System.out.println ("Fourth Condition true");
        System.out.println (City.walls[x--][y]);
        return false;
    }

Even if City.walls[x--][y]) is false, and System.out.println confirms this by printing out false, it will still enter the if statement, no matter what. What am I doing wrong with the comparison? Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-12T14:32:03+00:00Added an answer on June 12, 2026 at 2:32 pm

    You are using x–, which changes the value of x. First it returns the value, then it decrements the value:

    int x = 5;
    System.out.println(x--); //outputs 5
    System.out.println(x);   //outputs 4
    

    You probably want to say x-1

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