Question

This is because the string is got from a ResultSet which returns no value if the string is accessed again.

My position is like this.

ResultSet rst  = pst.executeQuery(); //pst is a preparedstatement
value = Integer.parseInt(rst.getString(1).trim().substring(0,<need to get position of '.' here>)

If I give rst.getString(1) again, it gives me an exception as no data found.

I have a workaround to store the string in a temporary variable and access it.

I needed to know if there was something like ‘this’ object to access the current string within a function of that string.

Thanks

Answer 1

You can save rst.getString(1) to new string variable

String st=rst.getString(1);

or use somthing like this

rst.getString(1).split(“\.”)[0].trim()