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Home/ Questions/Q 6327311
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:15:16+00:00 2026-05-24T17:15:16+00:00

This is code I have, but it looks like non-python. def __contains__(self, childName): Determines

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This is code I have, but it looks like non-python.

def __contains__(self, childName):
    """Determines if item is a child of this item"""
    for c in self.children:
        if c.name == childName:
            return True
    return False

What is the most “python” way of doing this? Use a lambda filter function? For some reason very few examples online actually work with a list of objects where you compare properties, they always show how to do this using a list of actual strings, but that’s not very realistic.

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:15:17+00:00Added an answer on May 24, 2026 at 5:15 pm

    I would use:

    return any(childName == c.name for c in self.children)
    

    This is short, and has the same advantage as your code, that it will stop when it finds the first match.

    If you’ll be doing this often, and speed is a concern, you can create a new attribute which is the set of child names, and then just use return childName in self.childNames, but then you have to update the methods that change children to keep childNames current.

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