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Home/ Questions/Q 6981373
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:08:57+00:00 2026-05-27T18:08:57+00:00

this is code that computes factorial of an arbitrary number: unsigned long long factorial(int

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this is code that computes factorial of an arbitrary number:

unsigned long long factorial(int n)
{
  Concurrency::combinable<unsigned long long> products=Concurrency::combinable<unsigned long long>([]()->unsigned long long{return 1LL;});
  Concurrency::parallel_for(1, n+1, [&products](int i){products.local() *= i;});
  return products.combine([](unsigned long long lProduct, unsigned long long rProduct){ return lProduct*rProduct;  });
}

can u please explain to me:

    • what does ()-> mean? i think () is a functor, but of which class? and why is there ->?
    • what is 1LL?
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:08:58+00:00Added an answer on May 27, 2026 at 6:08 pm

    ->unsigned long long declares the return type of the lambda function.

    You can google on C++ lambda for more information, but be basic syntax is something like:

    [capture_mode] (formal_parameters) mutable -> return_type {body}
    

    1LL is basically the same as static_cast<long long>(1). 1 is an int, 1LL is a long long.

    However, a shorter way to write it would have been:

    Concurrency::combinable([]{return 1ULL;});
    

    Where the types should be automatically deduced. Note that I used ULL instead of LL to make it an unsigned long long, as in the original code.

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