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Home/ Questions/Q 887441
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:13:49+00:00 2026-05-15T13:13:49+00:00

This is driving me crazy: I have function void gst_init(int *argc, char **argv[]); in

  • 0

This is driving me crazy:

I have function

void gst_init(int *argc, char **argv[]);

in the gstreamer api and I want to call it with some parameters I define, like:

int argc = 2;
char* argv[2] = {"myvalue1", "myvalue2"};
gst_init(&argc, &argv);

This code doesn’t compile (I get error C2664):

error C2664: 'gst_init' : cannot convert parameter 2 from 'char *(*)[2]' to 'char **[]'

The question: How do I define the argv value to pass it as a parameter? I’ve been using C++ for over 5 years, but I haven’t used a raw array since … high-school I think (more than five years ago).

Edit: I’m using VS2010 Express.

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:13:50+00:00Added an answer on May 15, 2026 at 1:13 pm

    Try

    int argc = 2;
    char* arg1[1] = {"myvalue1"};
    char* arg2[1] = {"myvalue2"};
    char** argv[2] = { arg1, arg2 };
    gst_init(&argc, argv);
    

    char **argv[] is an array of char**, which is analogous to an array of char* arrays.

    OTOH what you tried to pass as parameter is shown as char *(*)[2]: a pointer to an array of char*.

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