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Home/ Questions/Q 532195
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:22:47+00:00 2026-05-13T09:22:47+00:00

This is duplicate of Can XmlSerializer deserialize into a Nullable<int>? but I need a

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This is duplicate of Can XmlSerializer deserialize into a Nullable<int>? but I need a solution that neither change xml document nor forces me to implement IXmlSerializable interface. I dont want to implement IXmlSerializable because I have many additional elements beside <number> that get deserialized correctly.

My xml can contain either element <number>4</number> or <number/>

<root>
...
either <number>4</number> or <number/>
... [other elements]
</root>

Class

public class root
{
public int? number {get; set;}
...
}

does not work.

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:22:48+00:00Added an answer on May 13, 2026 at 9:22 am

    You can just use a surrogate property.

    public class MyType1
    {
        // XmlIgnore means it is not directly serialized
        [XmlIgnore]
        public int? number
        {
            get; set;
        }
    
        // acts as a surrogate for the nullable property
        [XmlElement("number")]
        public string _number_Surrogate
        {
            get
            {
                return (number.HasValue) ? number.ToString() : "";
            }
            set
            {
                if (!value.Equals(""))
                {
                    number = Int32.Parse(value);
                }
            }
        }
    
        public System.DateTime Time
        {
            get; set;
        }
    }
    
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