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Home/ Questions/Q 7012559
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T22:16:19+00:00 2026-05-27T22:16:19+00:00

This is getting ridiculous… Why do I get an error when I try to

  • 0

This is getting ridiculous…

Why do I get an error when I try to do this?

#...codecodecode...

g = generateGuid()

#...codecodecode...

generateGuid = ->
  "xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx".replace /[xy]/g, (c) ->
    r = Math.random() * 16 | 0
    v = (if c is "x" then r else (r & 0x3 | 0x8))
    v.toString 16

All I want to do is call a private function…

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  1. Editorial Team
    Editorial Team
    2026-05-27T22:16:20+00:00Added an answer on May 27, 2026 at 10:16 pm

    driis is correct. To expand on his answer: You may be used to the JavaScript idiom

    function generateGuid() { ... }
    

    which allows you to call generateGuid from anywhere within its scope (even before its definition). CoffeeScript doesn’t do this; instead, it compiles to

    var generateGuid = function() { ... }
    

    There are several reasons for doing this, but the long and short of it is that functions obey the same scoping rules as all other variables. Before a value has been assigned to generateGuid, generateGuid() is an attempt to call undefined.

    Note that, due to the way asynchronous callbacks work in JavaScript, this will work:

    setTimeout (->
      g = generateGuid
      # ...codecodecode...
    ), 0
    
    generateGuid = -> ...
    
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