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Home/ Questions/Q 886731
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:07:02+00:00 2026-05-15T13:07:02+00:00

This is how I do it currently: ref class Base abstract {}; ref class

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This is how I do it currently:

ref class Base abstract {};
ref class ConcreteClass1 : public Base {};
ref class ConcreteClass2 : public Base {};
(...and even more...)

void DoStuff(Base ^base)
{
   System::Type ^type = base->GetType();
   System::String ^name = type->Name;

   if(name == "ConcreteClass1")
          DoOtherStuff((ConcreteClass1 ^) base);
   else if(name == "ConcreteClass2")
          DoOtherStuff((ConcreteClass2 ^) base);
   (...and even more...)
}

Is there a more “elegant” way to do this?

With my approach, I have to add a new else if for every new Concrete Class, which makes me feel like one of the examples on thedailywtf.com.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:07:02+00:00Added an answer on May 15, 2026 at 1:07 pm

    Well, one simple thing you could do to make this more elegant would be to compare the types directly instead of using strings and type names:

    void DoStuff(Base ^base)
    {
       System::Type ^type = base->GetType();
    
       if(type == ConcreteClass1::typeid)
              DoOtherStuff((ConcreteClass1 ^) base);
       else if(type == ConcreteClass2::typeid)
              DoOtherStuff((ConcreteClass2 ^) base);
       (...and even more...)
    }
    

    However, this has quite a bit of “code smell” to it. Typically, the entire point of using abstract classes is to allow for polymorphism – if you can make DoOtherStuff a virtual function on each type, you could just do:

    base->DoOtherStuff();
    

    And the appropriate method will get called for you…

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