Question

This is how im generating my date i want to add 1 year to it. Thanks in advance.

char tmpbuf[128];
time_t ltime;
struct tm *today;
stringstream reD;
string todayDate;
time( &ltime );
today = localtime( &ltime );
strftime( tmpbuf, 128,"%Y-%m-%d_%H:%M:%S", today );
reD << tmpbuf;
reD >> todayDate;
boost::replace_all(todayDate, "_", " ");
cout << todayDate << endl;

OK ive decided to go with boost since it will be easier to add days, so 2 examples i need one to add 1 year, and one to add 14 days, heres what i have so fare

 #include "boost/date_time.hpp"
 #include "boost/date_time/local_time/local_time.hpp"

 using namespace boost::posix_time;
 using namespace boost::local_time;

 int main(){
    local_date_time t = local_sec_clock::local_time(time_zone_ptr());
    local_time_facet* lf(new local_time_facet("%Y-%m-%d_%H:%M:%S"));
    std::cout.imbue(std::locale(std::cout.getloc(), lf));
    std::cout << t << std::endl;
    return 0;
 }

Edit putting time into string

 stringstream reD;
 reD.imbue(locale(reD.getloc(), lf));
 reD << t;
 bthis = reD.str();
 cout << bthis << endl;

Answer 1

I agree about using boost::date_time, however, the solution here is quite easy.

today->tm_year++;

Although, if you happen to call localtime again, the value will be overwritten, so you should make a copy. Make today an instance instead of a pointer, and dereference the return value of localtime like this:

today = *localtime( &ltime );

You’ll have to take into account certain anomalies, like incrementing a year from February 29th on a leap year.

Edit: I see you’ve decided to use boost::date_time after all. This makes things much simpler. Here’s how you add a year:

t += boost::gregorian::years(1);

And here’s how you add 14 days:

t += boost::gregorian::days(14);

Or

t += boost::gregorian::weeks(2);