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Home/ Questions/Q 171703
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Asked: May 11, 20262026-05-11T13:02:05+00:00 2026-05-11T13:02:05+00:00

This is kinda weird. I have the next query: SELECT * , GROUP_CONCAT( x.tag

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This is kinda weird. I have the next query:

SELECT * , GROUP_CONCAT( x.tag SEPARATOR ',' ) AS tags FROM tag AS t, tag AS x, tag_message_rel AS r, message m INNER JOIN `user` AS u ON m.user_id = u.id WHERE t.tag IN ( 'kikikiki', 'dsa' ) AND m.id = r.message_id AND t.id = r.tag_id AND x.id = r.tag_id GROUP BY m.id HAVING COUNT( * ) >=2 ORDER BY m.created_at DESC LIMIT 0 , 20 

As you can see i use t to join find the messages that i want, on the other side i use x to print the tags of a message. I i erase the line:

AND x.id = r.tag_id 

I will get the messages that i want, but tags will have ALL the tags in the tags table separated by coma. If i leave the line there, i will only get those 2 tags. If i use explain i get:

id  select_type     table   type    possible_keys   key     key_len     ref     rows    Extra 1   SIMPLE  u   system  PRIMARY     NULL    NULL    NULL    1   Using temporary; Using filesort 1   SIMPLE  t   range   PRIMARY,tag     tag     252     NULL    2   Using where 1   SIMPLE  x   eq_ref  PRIMARY     PRIMARY     4   verse.t.id  1     1   SIMPLE  r   ALL     NULL    NULL    NULL    NULL    180     Using where; Using join buffer 1   SIMPLE  m   eq_ref  PRIMARY     PRIMARY     4   verse.r.message_id  1   Using where 

Now im no expert in this, but i think the problem is that it is refusing to re-join a table in the process of optimizing the query.

What do you think? Any quick fix?

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  1. 2026-05-11T13:02:06+00:00Added an answer on May 11, 2026 at 1:02 pm

    The problem is that you are trying to join to the tag table twice, but you really need to join to the tag_message_rel table twice, and from each of these to the respective row in the tag table.

    Think of ‘table aliases’ as referring to a row in a table, not the table itself. That idea helped me to understand complex joins a lot better.

    Here’s how I’d write that query:

    SELECT m.*, u.*, GROUP_CONCAT(DISTINCT x.tag) AS tags FROM message m  JOIN `user` u ON (u.id = m.user_id)  JOIN tag_message_rel r1 ON (m.id = r1.message_id)  JOIN tag t ON (t.id = r1.tag_id)  JOIN tag_message_rel r2 ON (m.id = r2.message_id)  JOIN tag x ON (x.id = r2.tag_id) WHERE t.tag IN ('kikikiki', 'dsa') GROUP BY m.id HAVING COUNT(DISTINCT t.tag) = 2 ORDER BY m.created_at DESC LIMIT 0 , 20; 

    You should develop the habit of using JOIN syntax consistently. Mixing JOIN and comma-style joins can cause some subtle problems.

    Here’s an alternative query, that pulls some of the joins into a non-correlated subquery, so you avoid a Cartesian product between t and x, and eliminate the DISTINCT modifiers in the group functions.

    SELECT m.*, u.*, GROUP_CONCAT(x.tag) AS tags FROM message m  JOIN `user` u ON (u.id = m.user_id)  JOIN tag_message_rel r ON (m.id = r.message_id)  JOIN tag x ON (x.id = r.tag_id) WHERE m.id = ANY (     SELECT m2.id      FROM message m2       JOIN tag_message_rel r2 ON (m2.id = r2.message_id)      JOIN tag t ON (t.id = r2.tag_id)     WHERE t.tag IN ('kikikiki', 'dsa')      GROUP BY m2.id      HAVING COUNT(t.tag) = 2) GROUP BY m.id ORDER BY m.created_at DESC LIMIT 0 , 20; 
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