Question

This is locale specific to the US wherein it considered that the start of a week is Sunday; I want to be able to ask SQL to give me the date of the next Sunday relative to today [getDate()]. If today is Jan 15 it should return Jan 18; if today were Sunday it should return the following Sunday which is the 25th. This would be trivial to write a UDF for but I was curious if anyone had other tricks/ideas?

Answer 1

DECLARE @d AS datetime SET @d = '1/15/2009' PRINT @d PRINT DATEADD(day, 8 - DATEPART(weekday, @d), @d) SET @d = '1/18/2009' PRINT @d PRINT DATEADD(day, 8 - DATEPART(weekday, @d), @d)  -- So it should be able to be used inline pretty efficiently: DATEADD(day, 8 - DATEPART(weekday, datecolumn), datecolumn)  -- If you want to change the first day for a different convention, simply use SET DATEFIRST before performing the operation -- e.g. for Monday: SET DATEFIRST 1 -- e.g. for Saturday: SET DATEFIRST 6  DECLARE @restore AS int SET @restore = @@DATEFIRST SET DATEFIRST 1  DECLARE @d AS datetime SET @d = '1/15/2009' PRINT @d PRINT DATEADD(day, 8 - DATEPART(weekday, @d), @d) SET @d = '1/19/2009' PRINT @d  PRINT DATEADD(day, 8 - DATEPART(weekday, @d), @d) SET DATEFIRST @restore