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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T01:58:56+00:00 2026-05-28T01:58:56+00:00

This is most likely a very obvious answer, but I am just not seeing

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This is most likely a very obvious answer, but I am just not seeing it. I want to open the phone application when I click a button.

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel://???????"]];

That line of code should do it. The problem is, depending on what happens in the app, I want it to dial a different number. I made a string variable, and I want to put it into the space with the ???

Something like:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel://(myPhoneNumberString)"]];

Any ideas?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-28T01:58:57+00:00Added an answer on May 28, 2026 at 1:58 am

    Take a look at the NSString documentation.

    Something like that will work:

    [ NSURL URLWithString: [ NSString stringWithFormat: @"tel://%@", myPhoneNumberStringVar ]
    

    String format is basically the same as in the printf C function, with the additional %@ format, used to print object representations.

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