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Asked: 2026-05-13T19:54:54+00:00

This is mostly for curiosity’s sake, as there are better ways of implementing almost

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This is mostly for curiosity’s sake, as there are better ways of implementing almost any use case I can think of for this construct (in C# and other languages I use regularly, at least), but I recently saw on here a scoped mutex which was a cool concept.

My question is, does the using statement maintain a reference (ie: prevent the GC from running on) to the object it’s acting on?

For example, if I were to do:

using (new ScopedMutex())
{
// ...
}

would the ScopedMutex object maintain its existence to the end of the using block, or could the GC run and dispose of it mid-block?

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1 Answer

  1. Editorial Team

    No, the GC will not dispose it. A reference to that object is stored in a local variable (see this answer for more info). A local variable is considered a GC root and the object will be reachable from it (it needs to be reachable for the using block to be able to call Dispose on it).

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