Question

This is my c code:

#include <stdio.h>


int main(){

int x[] = {6,1,2,3,4,5};
int *p=0;
p =&x[0];


while(*p!='\0'){

    printf("%d",*p);
    p++;
}

return 0;


}

When run the output is 612345-448304448336

What are the digits after the minus sign and why is my code giving this?

Answer 1

The condition *p != '\0', which is the same as *p != 0, is never met because your array doesn’t contain an element of value 0, and thus you overrun the array bounds and step into undefined behaviour.

Instead, you should control the array range directly:

for (int const * p = x; p != x + sizeof(x)/sizeof(x[0]); ++p)  // or "p != x + 6"
{
    printf("%d", *p);
}