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Home/ Questions/Q 7723033
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T04:20:27+00:00 2026-06-01T04:20:27+00:00

this is my class: class toyota extends car { function drive() { } function

  • 0

this is my class:

class toyota extends car {
    function drive() {
    }
    function break() {
    }
}

class car {
    function pre() {
    }
}

Is there any way I can do so that when I run $car->drive(), $car->break() (or any other function in toyota), it would call $car->pre() first before calling the functions in toyota?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T04:20:28+00:00Added an answer on June 1, 2026 at 4:20 am

    Yep. You could use protected and some __call magic:

    class toyota extends car {
        protected function drive() {
            echo "drive\n";
        }
        protected function dobreak() {
            echo "break\n";
        }
    }
    
    class car {
        public function __call($name, $args)
        {
            if (method_exists($this, $name)) {
                $this->pre();
                return call_user_func_array(array($this, $name), $args);
            }
    
    
        }
    
        function pre() {
            echo "pre\n";
        }
    }
    
    $car = new toyota();
    $car->drive();
    $car->dobreak();
    

    http://ideone.com/SGi1g

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