Question

This is my code:

$bookresult = mysqli_query($db, "SELECT bookID 
                                   FROM order_items 
                                  WHERE orderID = '".$orders['orderID']."';");

The problem I have is that there are multiple bookIDs that are pulled out of MySQL. So when I do this:

$books = mysqli_fetch_array($bookresult);

There is no way for me to get all the bookIDs that should show when using that select statement, unless I’m doing something wrong.

Answer 1

You need to use a loop to go through all of the values.

You can view them by using the following php code.
(You can use mysql_fetch_array in place of mysql_fetch_assoc if you wish.

while ($books_row = mysql_fetch_assoc($bookresult)) {
  //output here.
  echo "<pre>";
  print_r($books_row);
  echo "</pre>";
}

The output there is great for debugging…replace it with what you think is best after you solve this problem. 🙂
Hope this helped.