Question

This is my code.

File file = new File("src/qrcodescanner/xmlpac/"+filename);
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder(); 
document = db.parse(file);
document.getDocumentElement().normalize();

Answer 1

If it can’t be red it most probably isn’t where you expect it to be. Judging by the code you posted I suppose that your xml file is intended to reside inside your jar/package structure.

This is my test project structure:

src
 |-- main
     |-- java
         |-- mypackage
                 MyCode.java
                 MyResource.xml

The corresponding generated jar file is located at target/ directory and looks like this:

 mypackage
     MyCode.class
     MyResource.xml

MyResource.xml looks like this:

<a>b</a>

MyCode.java looks like this:

public class MyCode {

public static void main(String[] args) throws Exception {        
    String packagePath= "/mypackage/MyResource.xml";
    String myPath ="src/main/java"+packagePath;
    File f = new File(myPath);
    System.out.println(f.exists());        
    InputStream is = Class.class.getResourceAsStream(packagePath);                
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    DocumentBuilder db = dbf.newDocumentBuilder(); 
    Document d = db.parse(is);
    System.out.println(d.getElementsByTagName("a").item(0).getTextContent());         
    }    
}

When run it prints:

true
b

Method getResourceAsStream is used for loading resources from inside the JAR. Hope that helps.