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Home/ Questions/Q 7732023
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:37:41+00:00 2026-06-01T06:37:41+00:00

This is my code for counting lines and words: import System.IO import Data.List main

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This is my code for counting lines and words:

import System.IO
import Data.List
main = do
        hSetBinaryMode stdin True
        interact $ (\(w,l)->"line:"++(show l)++"\nwords:"++(show w)++"\n")
                   . foldl' (\(w,l) r-> w `seq` l `seq` (w+length r ,succ l) ) (0,0)
                   . lines

This takes about 10 seconds to run on a file of about 100 megabytes. I compared it to similar programs in Lua (9s), awk (20s), and wc -l -c (0.6s).

Why is this code so slow? What could be the problem?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:37:42+00:00Added an answer on June 1, 2026 at 6:37 am

    I/O with String is known to be less than fast in Haskell. The bytes read from the handle in general have to be converted to Unicode code points, and then a linked list is built from those. That’s a lot of work causing a lot of allocation. In this case, the conversion to code points is a bit simpler, since you set stdin to binary mode, but the construction of the linked list of characters still takes a lot of time.

    Another small factor is that your line count is using Integer, but that’s minor and only plays a significant role when the I/O is up to speed.

    If you need fast I/O, you have to use a type better suited for that. One possibility is using ByteString, for example

    import Data.List
    import qualified Data.ByteString.Lazy.Char8 as C
    main = do
            txt <- C.getContents
            putStrLn $ (\(w,l)->"line:"++(show l)++"\nwords:"++(show w)++"\n"). foldl' (\(w,l) r-> w `seq` l `seq` (w+C.length r ,succ l) ) (0,0) . C.lines $ txt
    

    does the job on a 94MB file in 0.12s on my box (wc -l -c takes 0.06s), while the original using String took 4.4s. It can be optimised further,

    {-# LANGUAGE BangPatterns #-}
    import Data.List
    import qualified Data.ByteString.Lazy.Char8 as C
    main = do
            txt <- C.getContents
            putStrLn $ (\(w,l)->"line:"++(show l)++"\nwords:"++(show w)++"\n"). loop 0 0 . C.lines $ txt
    
    loop :: Int -> Int -> [C.ByteString] -> (Int,Int)
    loop !w !l (ln:lns) = loop (w + fromIntegral (C.length ln)) (l+1) lns
    loop w l _ = (w,l)
    

    takes only 0.08s, which is decent enough for me to stop optimising there (a similar change for the String version brings the time down to 3.6s for that).

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