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Home/ Questions/Q 8791271
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T22:49:11+00:00 2026-06-13T22:49:11+00:00

This is my code: function func(){ for(i=0; i < 5; i++){ alert(‘g’); } }

  • 0

This is my code:

function func(){
 for(i=0; i < 5; i++){
   alert('g');
 }
}

for(i=0; i < 5; i++){
  func();
  alert('h');
}

What I expected was: gggghgggghgggghgggghggggh

but what received was just ggggh

I found out that’s because there is function scope, not block scope in JS. What I’d like to know is how to preserve such a behavior. I mean to force something like block scope. Otherwise it’s very easy to make really nasty bugs – e.g. while using a function somebody else wrote or the one you wrote yourself, but a few months earlier.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T22:49:12+00:00Added an answer on June 13, 2026 at 10:49 pm

    This actually doesn’t have to do with function vs. block scope – it has to do with implicit global variables.

    The short story: You are accidentally creating a global variable in your for loop – if you use for(var i=0; rather than for(i=0; you’ll get the expected results.

    The slightly longer version:

    alert("typeof i: " + typeof i);
    // Alerts "typeof i: undefined"    
    function func() {
      // References the *global* variable `i`
      for(i=0; i < 5; i++){
        alert('g');
      }
    }
    
    // Creates a *global* variable `i` and sets it to 0
    for(i=0; i < 5; i++) {
       alert("i at start of iteration: " + i);
       // Alerts "i at start of iteration: 0"
       func();
       // `func` has just altered *global* state - here's the proof
       alert("i after call to func: " + i);
       // Alerts "i at start of iteration: 5"
       alert('h');
    }
    alert("typeof i: " + typeof i);
    // Alerts "typeof i: number
    // `i` is now in the global scope.
    
    // Left as an exercise for the reader:
    // try it again with `var i=0;` in both of the `for` loops.
    
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