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Home/ Questions/Q 7441071
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:57:09+00:00 2026-05-29T10:57:09+00:00

This is my code : HTML <div style="display:none;"> <div id="example"> <div class="child">Hello</div> </div> </div>

  • 0

This is my code :

HTML

<div style="display:none;">
    <div id="example">
        <div class="child">Hello</div>
    </div>    
</div>        

<div id="result"></div>

jQuery

htmlSedi="";
sedi(1);
sedi(2)
    
$("#result").append(htmlSedi);    

function sedi(param) {
    var htmlSede = $('#example');
    
    if(param==1)
        htmlSede.find('.child').hide();
    
    htmlSedi=htmlSedi+htmlSede.html();
}

the result I aspect is to get at least one "Hello" printed into the div result, but in fact it doesnt; I think the problem is on :

var htmlSede = $('#example');

which point to the same object. So, how can I create a new "instance" of #example?

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:57:13+00:00Added an answer on May 29, 2026 at 10:57 am

    You can use .clone() for this.

    $("#example").clone();
    

    jQuery Docs

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