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Home/ Questions/Q 9124049
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T06:29:06+00:00 2026-06-17T06:29:06+00:00

This is my code: #include <iostream> #include <string.h> using namespace std; string& operator+(string &

  • 0

This is my code:

#include <iostream>
#include <string.h>
using namespace std;

string& operator+(string & lhs, int & rhs) {
    char temp[255];
    itoa(rhs,temp,10);
    return lhs += temp;
}

int main() {
  string text = "test ";
  string result = text + 10;
}

The result is:

test.cpp: In function 'int main()':
test.cpp:15:26: error: no match for 'operator+' in 'text + 10'
test.cpp:15:26: note: candidates are:
/.../

And should be test 10.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T06:29:07+00:00Added an answer on June 17, 2026 at 6:29 am

    An rvalue (10) can’t bind to a non-const reference. You need to rewrite your operator+ to take either an int const & or just an int as its parameter.

    While you’re at it, you want to rewrite it so it doesn’t modify the left operand either. An operator += should modify its left operand, but an operator + should not.

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