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Home/ Questions/Q 8908017
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T03:04:24+00:00 2026-06-15T03:04:24+00:00

This is my code <?php $something = array(); while ($row = mysql_fetch_assoc($result)) { $something[]

  • 0

This is my code

<?php
$something = array(); 
while ($row = mysql_fetch_assoc($result)) { 
    $something[] = $row;
} 
mysql_close($con);
?>

<script type="text/javascript"> 
    some= <?php echo json_encode($something); ?>; 
</script>

The above code will generate:

[{"id":"1","title":"Ray","author":"Ray","thumb":"some source","views":"10000"}]

But I want to generate a json string like this:

[{"id":"1","title":"Ray","author":"Ray","image":{"cls":"image","thumb":"some source","views":"10000"}}]

Any help ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T03:04:26+00:00Added an answer on June 15, 2026 at 3:04 am

    json_encode encodes whatever object structure you have. If you want certain properties to be as sub-object, you have to create such object in memory..

    For instance, if you had

    $a = array("id"=>1, 
               "title"=>"Ray", 
               "image" => 
                   array(
                     "thumb"=>"some source",
                     "cls"=>"image"
                    )
               );
    

    it would encode in json in a similar way you are mentioning.

    This means that you have to loop through mysql results and create the new structure before. Then call json_encode on it.

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