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Home/ Questions/Q 7446443
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T12:19:12+00:00 2026-05-29T12:19:12+00:00

This is my code, trying to convert the second field of the line from

  • 0

This is my code, trying to convert the second field of the line from exponential into float.

outputrrd = processrrd.communicate()
(output, error) = outputrrd
output_lines = output.split('\n')
for line in output_lines:
    m = re.search(r"(.*): ", line)
    if m != None:
        felder = line.split(': ')
        epoch =  felder[0].strip(':')
        utc = epoch2normal(epoch).strip("\n")
        #print felder[1]
        data = float(felder[1])
        float_data = data * 10000000
        print float_data
        resultslist.append( utc + ' ' + hostname + ' ' +  float_data)

But, the program stops with this error:

File "/opt/omd/scripts/python/livestatus/rrdfetch-convert.py", line 156, in <module>
    data = float(felder[1])
ValueError: invalid literal for float(): 6,0865000000e-01

Does anyone know the reason?

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  1. Editorial Team
    Editorial Team
    2026-05-29T12:19:13+00:00Added an answer on May 29, 2026 at 12:19 pm

    The easy way is replace! One simple example:

    value=str('6,0865000000e-01')
    value2=value.replace(',', '.')
    float(value2)
    0.60865000000000002
    
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