Question

This is my controller action:

<EmployeeAuthorize()>
Function HRA_Table() As ActionResult

    ' get current employee's id
    Dim db1 As EmployeeDbContext = New EmployeeDbContext
    Dim user1 = db1.Tbl_Employees.Where(Function(e) e.Employee_EmailAddress = User.Identity.Name).Single()
    Dim empId = user1.Employee_ID
    Dim empSSN = user1.Employee_SSN

    Dim hra = db.Tbl_HRAs.Where(Function(x) x.SSN = empSSN)

    Return View(hra.ToList)

End Function

This is my model:

Public Class Tbl_HRA

    <Key()> Public Property HRA_ID() As Integer
    Public Property SSN() As String
    Public Property Height() As Double
    Public Property Weight() As Double
    Public Property Nic_EE() As String
    Public Property Nic_SP() As String
    Public Property BMI() As Double
    Public Property BP_S() As Double
    Public Property BP_D() As Double
    Public Property HDL() As Double
    Public Property LDL() As Double
    Public Property Tot_Chol() As Double
    Public Property Continine() As String
    Public Property Glucose() As Double
    Public Property Waist() As Double
    Public Property Hip() As Double
    Public Property Triglycerides() As Double
    Public Property A1C() As Double
    Public Property LDL_HDL() As Double

End Class

This is my view:

@ModelType IEnumerable(Of GemcoBlog.Tbl_HRA)

@Code
    Layout = Nothing
End Code

@For Each item In Model

    @item.Height

Next

The error I get is:

The ‘Height’ property on ‘Tbl_HRA’ could not be set to a ‘String’
value. You must set this property to a non-null value of type
‘Double’.

I can’t seem to understand why this error is occurring. I tried changing it to double based on some articles I read, but still it won’t work!

Thanks for your help.

Answer 1

From your comment, it appears that the column in the table is a varchar. As a result, your model must define it as a string. Try changing the height property to be as follows:

 Public Property Height() As String

Unfortunately, you can’t do type conversions directly in the LINQ to SQL implementation. If you want, you could project into another type (in the Select clause), but you would still need the immediate fetch (context.GetTable(Of T)) to have the types be equivalent between your database and the model.