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Home/ Questions/Q 1047641
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T16:20:02+00:00 2026-05-16T16:20:02+00:00

This is my first question on Stack Overflow. Apologies in advance if I don’t

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This is my first question on Stack Overflow. Apologies in advance if I don’t do things quite right while I’m learning how things work here.

Here is my code :

public void TestSerialize()
{
    ShoppingBag _shoppingBag = new ShoppingBag();
    Fruits _fruits = new Fruits();
    _fruits.testAttribute = "foo";

    Fruit[] fruit = new Fruit[2];
    fruit[0] = new Fruit("pineapple");
    fruit[1]= new Fruit("kiwi");

    _fruits.AddRange(fruit);

    _shoppingBag.Items = _fruits;

    Serialize<ShoppingBag>(_shoppingBag, @"C:\temp\shopping.xml");
}

public static void Serialize<T>(T objectToSerialize, string filePath) where T : class
{
    XmlSerializer serializer = new XmlSerializer(typeof(T));

    using (StreamWriter writer = new StreamWriter(filePath))
    {
        serializer.Serialize(writer, objectToSerialize);
    }
}

[Serializable]
public class ShoppingBag
{
    private Fruits _items;

    public Fruits Items
    {
        get { return _items; }
        set {_items = value; }
    }
}

public class Fruits : List<Fruit>
{
    public string testAttribute { get; set; }
}

[Serializable]
public class Fruit 
{
    public Fruit() { }

    public Fruit(string value)
    {
        Name = value;
    }

    [XmlAttribute("name")]
    public string Name { get; set; }
}

It produces this XML :

<?xml version="1.0" encoding="utf-8" ?> 
<ShoppingBag xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Items>
    <Fruit name="pineapple" /> 
    <Fruit name="kiwi" /> 
  </Items>
</ShoppingBag>

I don’t understand why I am not getting <Items testAttribute="foo">

Please can anyone tell me what I need to add to my code so that the Serializer will write this attribute out?

Thanks,

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T16:20:02+00:00Added an answer on May 16, 2026 at 4:20 pm

    Unfortunately, when serializing a collection the XmlSerializer doesn’t take into account the extra properties of that collection. It only considers the members that implement ICollection<T>. If you want to serialize extra attributes, you need to wrap the collection in another class that is not a collection itself.

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