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Editorial Team
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Asked: 2026-06-09T13:16:47+00:00

This is my first question regarding PHP so please bear with me. I’ve been

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This is my first question regarding PHP so please bear with me. I’ve been following tutorials from phpacademy.org.

I’m stuck on one tutorial where an intro to AJAX is given. I typed in the exact code as the tutor, still its not working on my end.

I searched alot for it but it didnt help one bit. Could anybody help me out here? Here’s my code:

<html>
<head>
<script type="text/javascript">
function load(){

if(window.XMLHttpRequest)
    xmlhttp=new XMLHttpRequest();
else
    xmlhttp=new ActiveXObject('Microsoft.XMLHTTP');

xmlhttp.onreadystatechange=function(){
if(xmlhttp.readyState==4 && xmlhttp.status==200){
    document.getElementsById('adiv').innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open('GET', 'AJAX.inc.php', true);
xmlhttp.send();
}
</script>
</head>
<body>
<div id="adiv"></div>
<input type="submit" value="Submit" onclick="load();">
</body>
</html>

And here’s the AJAX.inc.php file:

<?php
echo 'Hello AJAX';
?>

However another example from w3school.com is working.

Possible duplicate:
AJAX not working with XAMPP or is it just impossible

But this question isn’t properly answered (or I dont understand it). Would someone please clarify it?

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1 Answer

  1. Editorial Team

    There is no document.getElementsById method.

    document.getElementsById('adiv').innerHTML=xmlhttp.responseText;

    Should be 

    document.getElementById('adiv').innerHTML=xmlhttp.responseText;
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