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Home/ Questions/Q 6245437
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T12:30:21+00:00 2026-05-24T12:30:21+00:00

this is my first script-fu for gimp and it gives me illegal function when

  • 0

this is my first script-fu for gimp and it gives me “illegal function” when i try to execute it there.

(define
    (
        script-fu-c64ize
        filename
        width
        height
    )
    (let*
        (
            (image 0)
        )
        (image (gimp-file-load 1 filename filename))
        (gimp-image-scale-full image width height 2)
        (gimp-image-scale-full image (/ width 2) height 0)
        (gimp-image-convert-indexed image 1 4 16 FALSE FALSE "C64")
        (gimp-image-scale-full image (* 4 width) (* 4 height) 0)
        (drawable (car (gimp-image-get-active-layer image)))
        (gimp-file-save 1 image drawable filename filename)
        (gimp-image-delete image)
    )
)

maybe someone more experienced can spot the error and i feel i missed something fundamental (or it’s just a stupid mistake). i’m still struggling with the docs.

thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-24T12:30:21+00:00Added an answer on May 24, 2026 at 12:30 pm

    In

    (image (gimp-file-load 1 filename filename))
    

    you’re calling image as a function, but immediately before, it is bound to a number. Since numbers aren’t functions, this will result in an error.

    I’m not familiar with Script-fu, but if I were to guess, I’d replace the (image 0) binding form with the one above.

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